It is given that $A$ and $B$ are such that $P(A) = \frac{1}{4}$,$P(A|B) = \frac{1}{2}$,and $P(B|A) = \frac{2}{3}$. Then $P(B) = $?
- A$\frac{1}{3}$
- B$\frac{2}{3}$
- C$\frac{1}{2}$
- D$\frac{1}{6}$
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MediumGUJCET 2026
View SolutionIf $A$ and $B$ are two independent events,then $A$ and $\bar{B}$ are
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